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NEW QUESTION: 1
Which statement is true regarding the UDP checksum?
A. It is used by some Internet worms to hide their propagation.
B. It is used for congestion control.
C. It cannot be all zeros.
D. It is computed based on the IP pseudo-header.
Answer: D
Explanation:
The method used to compute the checksum is defined in RFC 768: "Checksum is the 16-bit one's complement of the one's complement sum of a pseudo header of information from the IP header, the UDP header, and the data, padded with zero octets at the end (if necessary) to make a multiple of two octets." In other words, all 16-bit words are summed using one's complement arithmetic. Add the 16-bit values up. Each time a carry-out (17th bit) is produced, swing that bit around and add it back into the least significant bit. The sum is then one's complemented to yield the value of the UDP checksum field. If the checksum calculation results in the value zero (all 16 bits 0) it should be sent as the one's complement (all 1s).
ReferencE. http://en.wikipedia.org/wiki/User_Datagram_Protocol
NEW QUESTION: 2
What is system provisioning?
A. No basis on site some initial setup needs to occur Countries' currencies and end users need to be created
If integration is occurring all systems involved must be defined
B. On the SAP Fiori Launchpad Home, select Display Supplier Balances.
C. In the Supplier filter field, enter your supplier/employee number and select Go. You see two items open,
the invoice and the partial payment. No clearing has taken place.
D. Enter 1000 in the Allocated Amount field.
Answer: A
NEW QUESTION: 3
An EMC NetWorker storage node has two advanced file type devices that stage the data to two physical LTO-4 drives. Due to a hardware issue, the administrator has put one of the LTO-4 drives in Service mode.
How many nsrmmd processes are now running on the EMC NetWorker storage node?
A. 0
B. 1
C. 2
D. 3
Answer: A
NEW QUESTION: 4
Refer to the exhibit.
A packet is being sent across router R1 to host 172.16.0.14. What is the destination route for the packet?
A. 209.165.200.254 via Serial0/0/1
B. 209.165.200.250 via Serial0/0/0
C. 209.165.200.246 via Serial0/1/0
D. 209.165.200.254 via Serial0/0/0
Answer: C
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