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NEW QUESTION: 1
The developer wants to write a portable criteria query that will order the orders made by customer James Brown according to increasing quantity. Which one of the below queries correctly accomplishes that task?
A. CriteriaBuilder cb= . . .
CriteriaQuery<order> cq = cb.createquery<order.class>
Root <customer, order> 0 = cq.from(customer.class);
Join <customer, order> 0 = c.Join(customer-.orders);
cq.where (cb.equal(c.get(customer_.name, James Brown)));
cq.orderBy (0.get (order_.quantity));
cq.select(0);
B. CriteriaBuilder cb= . . .
CriteriaQuery<order> cq = cb.createquery<order.class>
Root <customer, order> 0 = cq.from(customer.class);
Join <customer, order> 0 = c.Join(customer-.orders);
cq.where (cb.equal(c.get(customer_.name, James Brown)));
cq.orderBy (0.get (order_.quantity));
cq.orderBy ("quantity");
C. CriteriaBuilder cb= . . .
CriteriaQuery<order> cq = cb.createquery<order.class>
Root <customer, order> 0 = cq.from(customer.class);
Join <customer, order> 0 = c.Join(customer-.orders);
cq.where (cb.equal(c.get(customer_.name, James Brown)));
cq.orderBy (0.get (order_.quantity));
D. CriteriaBuilder cb= . . .
CriteriaQuery<order> cq = cb.createquery<order.class>
Root <customer, order> 0 = cq.from(customer.class);
Join <customer, order> 0 = c.Join(customer-.orders);
cq.where (cb.equal(c.get(customer_.name, James Brown))); cq.select(0);
cq.orderBy (0.get (order_.quantity));
Answer: A
NEW QUESTION: 2
Sie entwickeln eine Datenbank, die Preisinformationen enthält.
Sie müssen die Preise speichern, die eine feste Genauigkeit und eine sechsstellige Skala enthalten.
Welchen Datentyp sollten Sie verwenden?
A. Float
B. Kleines Geld
C. Dezimalzahl
D. Geld
Answer: C
Explanation:
Decimal is the only one in the list that can give a fixed precision and scale.
Reference:
http://msdn.microsoft.com/en-us/library/ms187746.aspx
NEW QUESTION: 3
Refer to the exhibit. Which command is simplest to configure routing between the regional office network 10.89.0.0/20 and the corporate network?
A. router1(config)#ip route 10.89.0.0 255.255.240.0 10.89.16.2
B. router1(config)#ip route 10.89.0.0 255.255.240.0 10.89.16.1
C. router2(config)#ip route 0.0.0.0 0.0.0.0 10.89.16.1
D. router2(config)#ip route 10.89.3.0 255.255.0.0 10.89.16.2
Answer: C
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