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NEW QUESTION: 1
Refer to the exhibit.
AS #1 and AS #2 have multiple EBGP connections with each other. AS #1 wants all return traffic that is destined to the prefix 10.10.10.1/32 to enter through the router R1 from AS #2. In order to achieve this routing policy, the AS 1 advertises a lower MED from R1, compared to a higher MED from R3, to their respective BGP neighbor for the prefix 10.10.10.0/24. Will this measure guarantee that the routing policy is always in effect?
A. Yes, because a lower MED in AS #2 is the highest BGP attribute in BGP best-path route selection.
B. No, AS #2 can choose to alter the local preference attribute to overwrite the best-path route selection over the lower MED advertisement from AS #1. This local preference attribute is cascaded across AS
#2 for the BGP best-path route selection.
C. No, AS #2 can choose to alter the weight attribute in R2 for BGP neighbor R1, and this weight value is cascaded across AS #2 for BGP best-path route selection.
D. Yes, because a lower MED forces BGP best-path route selection in AS #2 to choose R1 as the best path for 10.10.10.0/24.
E. Yes, because MED plays a deterministic role in return traffic engineering in BGP.
Answer: B
NEW QUESTION: 2
Sie verwalten eine Microsoft SQL Server 2012-Datenbank mit dem Namen ContosoDb. Die Tabellen sind wie im Exponat angegeben definiert. (Klicken Sie auf die Schaltfläche "Ausstellen".)
Sie müssen Zeilen aus der Orders-Tabelle für die Customers-Zeile mit dem CustomerId-Wert 1 im folgenden XML-Format anzeigen.
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FÜR XML AUTO
B. SELECT Name, Land, Bestell-ID, Bestelldatum, Betrag
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FÜR XML AUTO
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers = CustomerId = 1 FÜR XML RAW, ELEMENTS
D. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FÜR XML RAW
E. SELECT Name, Land, Bestell-ID, Bestelldatum, Betrag
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FÜR XML AUTO, ELEMENTS
F. SELECT Name AS '@Name', Land AS '@Country', OrderId, OrderDate, Betrag FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers' )
G. WÄHLEN Sie den Namen ALS "Kunden / Name", das Land ALS "Kunden / Land", die Bestellnummer, das Bestelldatum und den Auftragsbetrag INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH (' Kunden')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FÜR XML AUTO, ELEMENTS
Answer: E
NEW QUESTION: 3
The implementations group has been using the test bed to do a 'proof-of-concept' that requires both Client 1 and Client 2 to access the WEB Server at 209.65.200.241.
After several changes to the network addressing, routing scheme, DHCP services, NTP services, layer 2 connectivity, FHRP services, and device security, a trouble ticket has been opened indicating that Client 1 cannot ping the 209.65.200.241 address.
Use the supported commands to isolated the cause of this fault and answer the following questions.
Which is the solution to the fault condition?
A. Under the OSPF process, delete the redistribute eigrp10 subnets route-map EIGPR -
> OSPF command and enter the redistribute eigrp10 subnets route-map OSPF - > EIGRP command.
B. Under the EIGRP process, delete the redistribute ospf 1 route-map OSPF_ to_ EIGRP command and enter the redistribute ospf 1 route-map OSPF - > EIGRP command.
C. Under the OSPF process, delete the redistribute eigrp10 subnets route-map EIGPR -
> OSPF command and enter the redistribute eigrp10 subnets route-map EIGPR - > OSPF command.
D. Under the EIGRP process, delete the redistribute ospf 1 route-map OSPF_ to_ EIGRP command and enter the redistribute ospf 6 metric route-map OSPF - > EIGRP command.
E. Under the EIGRP process, delete the redistribute ospf 1 route-map OSPF _to_ EIGRP command and enter redistribute ospf 1 metric 100000 100 100 1 15000 route_ map OSPF
_to _EIGRP command
Answer: B
Explanation:
On R4, in the redistribution of EIGRP routing protocol, we need to change name of route- map to resolve the issue. It references route-map OSPF_to_EIGRP but the actual route map is called OSPF->EIGRP.
NEW QUESTION: 4
In GETVPN, which key in uned to necure the control plane?
A. mennage encryption key (MEK)
B. Key Encryption Key (KEK).
C. content encryption key (CEK)
D. Traffic Encryption Key (TEK)
Answer: B
Explanation:
GDOI introducen two different encryption keyn. One key necuren the GET VPN control plane; the other key necuren the
data traffic. The key uned to necure the control plane in commonly called the Key Encryption Key (KEK), and the key
uned to encrypt data traffic in known an Traffic Encryption Key (TEK).
Reference: Group Encrypted Trannport VPN (Get VPN) Denign and Implementation Guide PDF
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