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NEW QUESTION: 1
Which scheduling calculates the latest start and finish dates for all activities?
Please choose the correct answer.
A. Backward scheduling
B. Project based scheduling
C. Forward scheduling
D. Network based scheduling
Answer: C
NEW QUESTION: 2
CORRECT TEXT
-10.10.10.0/24
-190.200.250.32/27
-190.200.250.64/27
Answer:
Explanation:
There are two ways to configure interVLAN routing in this case:
+Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch.
Trunking must be established between RouterC and SwitchC.
+Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer 3 switch (which supports ip routing function as a router).
No trunking requires.
The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3
switch with SVIs for interVLAN routing.
We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways.
The Answer: \>ipconfig
We will get the default gateways as follows:
Host1:
+ Default gateway: 190.200.250.33
Host2:
+ Default gateway: 190.200.250.65
Now we have enough information to configure SwitchC (notice the EIGRP AS in this case
is 650)
Note: VLAN2 and VLAN3 were created and gi0/10, gi0/11 interfaces were configured as
access ports so we don't need to configure them in this sim.
SwitchC# configure terminal
SwitchC(config)# int gi0/1
SwitchC(config-if)#no switchport -> without using this command, the simulator does not
let you assign IP address on Gi0/1 interface.
SwitchC(config-if)# ip address 10.10.10.2 255.255.255.0 ->RouterC has used IP
10.10.10.1 so this is the lowest usable IP address.
SwitchC(config-if)# no shutdown
SwitchC(config-if)# exit
SwitchC(config)# int vlan 2
SwitchC(config-if)# ip address 190.200.250.33 255.255.255.224
SwitchC(config-if)# no shutdown
SwitchC(config-if)# int vlan 3
SwitchC(config-if)# ip address 190.200.250.65 255.255.255.224
SwitchC(config-if)# no shutdown
SwitchC(config-if)#exit
SwitchC(config)# ip routing (Notice: MLS will not work without this command)
SwitchC(config)# router eigrp 65010
SwitchC(config-router)# network 10.10.10.0 0.0.0.255
SwitchC(config-router)# network 190.200.250.32 0.0.0.31
SwitchC(config-router)# network 190.200.250.64 0.0.0.31
NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the
exam, also don't modify/delete any port just do the above configuration. Also some reports
said the "no auto-summary" command can't be used in the simulator, in fact it is not
necessary because the network 190.200.0.0/16 is not used anywhere else in this topology.
In order to complete the lab, you should expect the ping to SERVER to succeed from the
MLS, and from the PCs as well.
Also make sure you use the correct EIGRP AS number (in the configuration above it is 650
but it will change when you take the exam) but we are not allowed to access RouterC so
the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS
number, no neighbor relationship is formed between RouterC and SwitchC.
In fact, we are pretty sure instead of using two commands "network 190.200.250.32
0.0.0.31 and "network 190.200.250.64 0.0.0.31 we can use one simple command "network
190.200.0.0 because it is the nature of distance vector routing protocol like EIGRP: only
major networks need to be advertised; even without "no auto-summary" command the
network still works correctly. But in the exam the sim is just a flash based simulator so we
should use two above commands, just for sure. But after finishing the configuration, we can
use "show run" command to verify, only the summarized network 190.200.0.0 is shown.
NEW QUESTION: 3
Which is a valid CREATE TABLE statement?
A. CREATE TABLE 1EMP_TEST AS (empid number(2));
B. CREATE TABLE EMP9$# AS (empid number(2));
C. CREATE TABLE EMP*123 AS (empid number(2));
D. CREATE TABLE PACKAGE AS (packid number(2));
Answer: B
Explanation:
Explanation/Reference:
Explanation: Table names and column names must begin with a letter and be 1-30 characters long.
Characters A-Z, a-z, 0-9, _, $ and # (legal characters but their use is discouraged).
Incorrect answer:
B. Non alphanumeric character such as "*" is discourage in Oracle table name.
D. Table name must begin with a letter.
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 9-4
NEW QUESTION: 4
You have a SharePoint Server 2010 Service Pack 1 (SP1) server farm.
You plan to deploy a site for the sales department and a site for the finance department.
You identify the following search requirements for each site:
---
Content on the finance site must be indexed once daily.
Content on the sales site must be indexed every 15 minutes.
Each site must have independent search keywords and synonyms.
You need to recommend a logical structure to meet the search requirements of each site.
What should you recommend?
A. One site collection, two sites, and two content sources
B. One site collection, two sites, and two search scopes
C. Two sites collections, two sites, and two content sources
D. Two sites collections, two sites, and two search scopes
Answer: C