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NEW QUESTION: 1
Supermajority vote requirements and state dissolution statues are the factors that influence:
A. Lack of control discount
B. Blocking power
C. Swing vote
D. Ultimate rate of return produced by the interest.
Answer: A
NEW QUESTION: 2
Which Cisco Unified Communications Manager partition will be associated with a directory URI that is configured for an end user with a primary extension?
A. none
B. null
C. any partition that the Cisco Unified Communications Manager administrator desires
D. default
E. directory URI
Answer: E
Explanation:
Explanation/Reference:
Explanation:
Cisco Unified Communications Manager supports dialing using directory URIs for call addressing.
Directory URIs look like email addresses and follow the username@host format where the host portion is an IPv4 address or a fully qualified domain name. A directory URI is auniform resource identifier, a string of characters that can be used to identify a directory number. If that directory number is assigned to a phone, Cisco Unified Communications Manager can route calls to that phone using the directory URI. URI dialing is available for SIP and SCCP endpoints that support directory URIs.
NEW QUESTION: 3
アンは、代行受信プロキシを介してマーケティングWebサイトの堅牢性をテストしています。彼女は次のHTTPリクエストを傍受しました。
POST /login.aspx HTTP / 1.1
ホスト:comptia.org
コンテンツタイプ:text / html
txtUsername = ann&txtPassword = ann&alreadyLoggedIn = false&submit = true
Webサイトが単純な認証バイパスの影響を受けやすいかどうかをテストするために、アンは次のうちどれを実行する必要がありますか?
A. txtPassword投稿データを削除し、alreadyLoggedInをfalseからtrueに変更します
B. パスワードクラッカーを使用して、すべてのユーザー名とパスワードをブルートフォースで攻撃しようとする
C. txtUsernameおよびtxtPassword投稿データを削除し、送信をtrueからfalseに切り替えます
D. すべての投稿データを削除し、リクエストを/login.aspxにPOSTからGETに変更します
Answer: A
Explanation:
The text "txtUsername=ann&txtPassword=ann" is an attempted login using a username of `ann' and also a password of `ann'.
The text "alreadyLoggedIn=false" is saying that Ann is not already logged in. To test whether we can bypass the authentication, we can attempt the login without the password and we can see if we can bypass the `alreadyloggedin' check by changing alreadyLoggedIn from false to true. If we are able to log in, then we have bypassed the authentication check.