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NEW QUESTION: 1
A manager wants to review the cash balance by company. He has asked you to create the
summary account template. The company's accounting flexfield has four segments:
Company (5 values)
Cost Centers (30 values)
Region (4 values)
Account (180 values)
The total number of cash accounts is five that are associated with two parents:
Three accounts are associated with the parent called Checking.
Two accounts are identified with the parent called Savings.
To combine the cash parents, you created a rollup group named Cash.
How many accounts would the summary account template generate?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: C
NEW QUESTION: 2
A. Option C
B. Option B
C. Option A
D. Option D
Answer: C
NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:
Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
Answer: A
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1
NEW QUESTION: 4
Ein Techniker ersetzt einen defekten Bildschirm eines neuen Firmen-Laptops, hat jedoch keine Reparaturinformationen vom Hersteller.
Welche der folgenden Methoden ist die BESTE, um fortzufahren?
A. Dokumentieren und beschriften Sie die Kabel- und Schraubenpositionen.
B. Aktualisieren Sie die Firmware auf dem Gerät, bevor Sie es reparieren.
C. Warten Sie, bis der Anbieter weitere Informationen bereitstellt.
D. Ersetzen Sie den Bildschirm durch einen Nicht-OEM.
Answer: A