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NEW QUESTION: 1
A known IT service stops performing during normal business hours, then the user of the IT service calls
the service desk.
What should the service desk open?
A. An incident record
B. A service request
C. An emergency request
D. A problem record
Answer: B
NEW QUESTION: 2
An administrator is planning a Floating Linked-Clone desktop pool using local solid state drives. A stateless configuration is suitable for this group of users.
Local solid state drive capacity is limited. The administrator plans to use the storage tiering capabilities of View Composer to place the Linked-Clones on shared storage and place only the Replica on local disk.
Why will the administrator be prevented from using this configuration?
A. Replica and Linked-Clone disks must reside on the same datastore when using local disks.
B. Storage tiering is supported only for Dedicated Assignment Linked-Clone desktops.
C. Replica disks must always reside on shared storage for Linked-Clone pools.
D. Storage tiering is supported only when using Full Clone desktops.
Answer: A
NEW QUESTION: 3
A network administrator must enable which protocol extension to utilize EAP-Chaining?
A. EAP-TLS
B. MSCHAPv2
C. PEAP
D. EAP-FAST
Answer: D
NEW QUESTION: 4
Given:
import java.io.IOException;
import java.io.file.Path;
import java.io.file.Paths;
public class Path12 {
public static void main(String s[]) throws IOException {
Path path = Paths.get("\\sales\\quarter\\..\\qtrlreport.txt");
path.relativize(Paths.get("\\sales\\annualreport.txt"));
if(path.endsWith("annualreport.txt")) {
System.out.println(true);
} else {
System.out.println(false);
}
System.out.println(path);
}
}
What is the result?
A. false \quarter\ . . \qtrlreport.txt
B. false \sales\quarter\ . . \qtrlreport.txt
C. true \ . . \ . . \annualreport.txt
D. true . . \ . . \ . . \ annualreport.txt
Answer: B
Explanation:
The relativize method that can be used to construct a relative path between two paths.
relativize
Path relativize(Path other)
Constructs a relative path between this path and a given path.
Parameters:
other - the path to relativize against this path
Returns:
the resulting relative path, or an empty path if both paths are equal
Note:
Relativization is the inverse of resolution. This method attempts to construct a relative path
that when resolved against this path, yields a path that locates the same file as the given
path. For example, on UNIX, if this path is "/a/b" and the given path is "/a/b/c/d" then the
resulting relative path would be "c/d". Where this path and the given path do not have a
root component, then a relative path can be constructed. A relative path cannot be
constructed if only one of the paths have a root component. Where both paths have a root
component then it is implementation dependent if a relative path can be constructed. If this
path and the given path are equal then an empty path is returned.
For any two normalized paths p and q, where q does not have a root component,
p.relativize(p.resolve(q)).equals(q)
When symbolic links are supported, then whether the resulting path, when resolved against
this path, yields a path that can be used to locate the same file as other is implementation
dependent. For example, if this path is "/a/b" and the given path is "/a/x" then the resulting
relative path may be "../x". If "b" is a symbolic link then is implementation dependent if
"a/b/../x" would locate the same file as "/a/x".