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NEW QUESTION: 1
You design an Azure web application. The web application is accessible by default as a standard cloudapp.net URL.
You need to recommend a DNS resource record type that will allow you to configure access to the web application by using a custom domain name.
Which DNS record type should you recommend?
A. CNAME
B. SRV
C. MX
D. A
Answer: A
Explanation:
A CNAME record maps a specific domain, such as contoso.com or www.contoso.com, to a canonical domain name. In this case, the canonical domain name is the <myapp>.cloudapp.net domain name of your Azure hosted application. Once created, the CNAME creates an alias for the
<myapp>.cloudapp.net. The CNAME entry will resolve to the IP address of your <myapp>.cloudapp.net service automatically, so if the IP address of the cloud service changes, you do not have to take any action.
Incorrect:
Not D:
* Since an A record is mapped to a static IP address, it cannot automatically resolve changes to the IP address of your Cloud Service.
* An A record maps a domain, such as contoso.com or www.contoso.com, or a wildcard domain such as
*.contoso.com, to an IP address. In the case of an Azure Cloud Service, the virtual IP of the service. So the main benefit of an A record over a CNAME record is that you can have one entry that uses a wildcard, such as *.contoso.com, which would handle requests for multiple sub-domains such as mail.contoso.com, login.contoso.com, or www.contso.com.
Reference:
NEW QUESTION: 2
Hot Area:
Answer:
Explanation:
NEW QUESTION: 3
Refer to the exhibit. The company uses EIGRP as the routing protocol.
What path will packets take from a host on 192.168.10.192/26 network to a host on the LAN attached to
router R1?
A. The path of the packets will be both R3 to R2 to R1 and R3 to R1
B. The path of the packets will be R3 to R1 to R2
C. The path of the packets will be R3 to R2 to R1
D. The path of the packets will be R3 to R1
Answer: D
Explanation:
Explanation/Reference:
Explanation:
EIGRP Questions
Looking at the output display above, the LAN attached to router R1 belongs to 192.168.20.64/26 subnet
and learned this network via 192.168.20.9 which will be an IP address in 192.168.20.8/30 sub-network.
This means that packets destined for192.168.20.64 will be routed from R3 to R1.
Reference: http://www.9tut.net/icnd2/eigrp-questions
http://www.orbitco-ccna-pastquestions.com/CCNA---EIGRP-Common-Question.php