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NEW QUESTION: 1
A network architect is planning a guest solution for a group of ports in a conference room. Guests should have access to the internet only. The company wants a single solution prefers not to burden visitors with login requests.
Which solution would best meet the company's requirements for guest network?
A. Place the guest ports in a blackhole VLAN that is not carried on switch-to-switch links. Apply a Dynamic VLAN for guests who pass web authentication to a server that allows MAC registration.
B. Place the guest ports in a VLAN that is allowed access only to the internet. Optionally configure port isolation.
C. Apply MAC lockdown to the guest ports. Configure switches to place unknown MAC addresses in a VLAN with access only to the internet.
D. Apply web authentication to the guest ports. Use the built-in guest accounts for HP switches to authenticate the users.
Answer: B
NEW QUESTION: 2
Which option is a valid IPv6 address?
A. FEC0:ABCD:WXYZ:0067::2A4
B. 2004:1:25A4:886F::1
C. 2002:7654:A1AD:61:81AF:CCC1
D. 2001:0000:130F::099a::12a
Answer: B
Explanation:
IPv6 Address Notation
IPv6 addresses are denoted by eight groups of hexadecimal quartets separated by colons in between them.
Following is an example of a valid IPv6 address: 2001:cdba:0000:0000:0000:0000:3257:9652
Any four-digit group of zeroes within an IPv6 address may be reduced to a single zero or altogether omitted.
Therefore, the following IPv6 addresses are similar and equally valid:
2001:cdba:0000:0000:0000:0000:3257:9652
2001:cdba:0:0:0:0:3257:9652
2001:cdba::3257:9652
Reference: http://www.ipv6.com/articles/general/IPv6-Addressing.htm
NEW QUESTION: 3
Which technology can be affected when switches are used that do not support jumbo frames?
A. 802.1q
B. OSPFv3
C. BFD
D. 802.1x
Answer: A
Explanation:
The 802.1Q tag is 4 bytes. Therefore, the resulting Ethernet frame can be as large as 1522 bytes. If jumbo frames are not supported, then typically the MTU on an Ethernet link needs to be lowered to 1496 to support this extra 802.1Q tag.