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NEW QUESTION: 1
A developer is writing an application with three java Persistence API entities: order, customer, and Address. There is a many-to-one relationship between order and customer, and a one to-many relationship between customer and Address.
Which two Criteria queries will return the orders of all customers who have an address whose value specified by the String parameter postalcode? (Choose two)
A. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq.from (Order . class) ,
Join<order, Address> address = order.join(Customer_.addresses);
cq.where(ct>.equal(address.get(Address_.postalCode), postalCode));
cq-select(order).distinct(true);
// query execution code here
.. .
B. String postalCode = . . .
Criteria Builder cb = . . .
CriteriaQuery<order> cq = cb.createQuery (Order.class);
Root <order> order = cq.from(order.class);
Join <order, Customer> customer = order.join(Order_.customer);
Root <Order> order = cq.from (Order.class);
Join <customer, Address> address = customer join (Order_.customer)
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
.. .
C. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq.from (Order . class ) ,
Join<order, Address> address = order . join (Order_. customer).join (Customer_.addresses); cq.where <cb.equal (address.get(Address_.postalCode) , postalCode) ) ; cq.selec:(order).distinct (true);
// query execution code here
.. .
D. String postalCode = . . .
Criteria Builder cb = . . .
Root <Order> order = cq.from (Order.class);
order.join (order_. customer).join(Customer_.addresses);
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
Answer: B,C
Explanation:
Explanation/Reference:
A: Join Order and Customer and join Customer and Address. Works fine.
Not B: Chained joined not set up correctly.
C: Join Order and Address through first joining Order and Customer.
Not D: Cannot Join Order Address it just one single join. Need to chain the join.
Note: Querying Relationships Using Joins
For queries that navigate to related entity classes, the query must define a join to the related entity by calling one of the From.join methods on the query root object or another join object. The join methods are similar to the JOIN keyword in JPQL.
The target of the join uses the Metamodel class of type EntityType<T> to specify the persistent field or property of the joined entity.
The join methods return an object of type Join<X, Y>, where X is the source entity and Y is the target of the join. In the following code snippet, Pet is the source entity, Owner is the target, and Pet_ is a statically generated metamodel class:
CriteriaQuery<Pet> cq = cb.createQuery(Pet.class);
Root<Pet> pet = cq.from(Pet.class);
Join<Pet, Owner> owner = pet.join(Pet_.owners);
Joins can be chained together to navigate to related entities of the target entity without having to create a Join<X, Y> instance for each join:
CriteriaQuery<Pet> cq = cb.createQuery(Pet.class);
Root<Pet> pet = cq.from(Pet.class);
Join<Owner, Address> address = cq.join(Pet_.owners).join(Owner_.addresses); Reference: Using the Criteria API and Metamodel API to Create Basic Typesafe Queries
NEW QUESTION: 2
Which of the following is not a primary purpose for conducting a walk-through during the initial stages of an assurance engagement?
A. To test the adequacy of controls.
B. To determine segregation of duties.
C. To help develop process maps.
D. To identify residual risks.
Answer: A
NEW QUESTION: 3
Which two statements are true about an EPL? (Choose two.)
A. It is a point-to-point Ethernet connection between a pair of NNIs.
B. The EPL service is also referred to as E-line.
C. It has a high degree of transparency.
D. It allows for service multiplexing.
Answer: B,C
Explanation:
Explanation/Reference:
Explanation:
Ethernet private line (EPL) and Ethernet virtual private line (EVPL) are carrier Ethernet data services defined by the Metro Ethernet Forum. EPL provides a point-to-point Ethernet virtual connection (EVC) between a pair of dedicated usernetwork interfaces (UNIs), with a high degree of transparency. EVPL provides a point-to-point or point-to-multipoint connection between a pair of UNIs.
The services are categorized as an E-Line service type, with an expectation of low frame delay, frame delay variation and frame loss ratio. EPL is implemented using a point-to-point (EVC) with no Service Multiplexing at each UNI (physical interface), i.e., all service frames at the UNI are mapped to a single EVC (a.k.a. all-to-one bundling).
Reference. http://en.wikipedia.org/wiki/Ethernet_Private_Line
NEW QUESTION: 4
Which one of the following is NOT one of the five stated fundamental principles of CIMA's code of ethics?
A. Objectivity
B. Confidentiality
C. Punctuality
D. Integrity
Answer: C
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