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NEW QUESTION: 1
You are designing a table for a SQL Server database. The table uses horizontal partitioning.
You have the following requirements:
You need to choose the appropriate data type for the key value.
What should you do?
A. Generate a random value that uses the char(16) data type.
B. Use the NEWID function to create a unique identifier.
C. Use the NEWSEQUENTIALID function to create a unique identifier.
D. Generate a random value that uses the bigint datatype.
Answer: C
Explanation:
Horizontal partitioning divides a table into multiple tables. Each table then contains the same number of columns, but fewer rows. For example, a table that contains 1 billion rows could be partitioned horizontally into 12 tables, with each smaller table representing one month of data for a specific year.
Any queries requiring data for a specific month only reference the appropriate table.
NEWSEQUENTIALID creates a GUID that is greater than any GUID previously generated by this function on a specified computer since Windows was started. After restarting Windows, the GUID can start again from a lower range, but is still globally unique. When a GUID column is used as a row identifier, using NEWSEQUENTIALID can be faster than using the NEWID function. This is because the NEWID function causes random activity and uses fewer cached data pages. Using NEWSEQUENTIALID also helps to completely fill the data and index pages.
References:https://msdn.microsoft.com/en-us/library/ms189786.aspx
NEW QUESTION: 2
공개 키 암호화 시스템에서 개인 정보를 보호하기 위해 수신 된 메시지를 해독하려면 다음 키 중 어느 것이 필요합니까?
I. 개인
II.
공공의
A. I.
B. II.
C. l과 ll. D 나도 IL도
Answer: A
Explanation:
In a public key system, the public key is used to encrypt the message prior to transmission, whereas the private key is needed to decrypt decode) the message.
NEW QUESTION: 3
Which two statements are Datastore Cluster requirements? (Choose two.)
A. Datastore clusters must contain three or more datastores.
B. Datastores shared across multiple data centers cannot be included in a datastore cluster.
C. NFS and VMFS datastores cannot cannot be combined in the same datastore cluster.
D. Datastore clusters can only contain VMFS datastores.
Answer: B,C
Explanation:
Explanation: References:
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