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NEW QUESTION: 1
A company needs to cost-effectively persist small data records (up to 1 KiB) for up to 30 days. The data is read rarely. When reading the data, a 5-minute delay is acceptable.
Which of the following solutions achieve this goal? (Choose two.)
A. Use Amazon S3 to collect multiple records in one S3 object. Use a lifecycle configuration to move data to Amazon Glacier immediately after write. Use expedited retrievals when reading the data.
B. Write the records to Amazon DynamoDB configured with a Time To Live (TTL) of 30 days. Read data using the GetItem or BatchGetItem call.
C. Use an AWS Lambda function invoked via Amazon API Gateway to collect data for 5 minutes. Write data to Amazon S3 just before the Lambda execution stops.
D. Write the records to Amazon Kinesis Data Firehose and configure Kinesis Data Firehose to deliver the data to Amazon S3 after 5 minutes. Set an expiration action at 30 days on the S3 bucket.
E. Write the records to an Amazon ElastiCache for Redis. Configure the Redis append-only file (AOF) persistence logs to write to Amazon S3. Recover from the log if the ElastiCache instance has failed.
Answer: B,D
NEW QUESTION: 2
A. Option D
B. Option C
C. Option B
D. Option A
Answer: D
NEW QUESTION: 3
You are managing a Google AdWords account for your company. Your manager informs you that she wants you to create a daily budget of $75 and hit this budget everyday in Google ads, but also get the most clicks as possible for this budget. Considering this scenario, which of the
following tools will help you hit your daily budget of $75, and still maximize the clicks you receive?
A. Use the conversion optimizer
B. Use the ad scheduling option
C. Use a CPM ad campaign
D. Use the automatic bidding option
Answer: D
NEW QUESTION: 4
Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
A. The network is not subnetted.
B. The subnet address is 10.16.3.0 255.255.254.0.
C. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
D. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
E. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
Answer: C,D
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are
2.1 through 3.254
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