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NEW QUESTION: 1
A Cisco Unified Wireless Network has an AP that does not rely on the central control device of the network. Which type of AP has this characteristic?
A. Rogue AP
B. Autonomous AP
C. LWAPP
D. Lightweight AP
Answer: B
Explanation:
Autonomous Access Point is an AP that does not rely on the central control device. It is also called Standalone Access Point. The home office, corporate office, or a Wi-Fihot-spotwill have autonomous access points. Autonomous AP is deployed as a standalone device in ISR routers at branch sites. Answer option C is incorrect. Lightweight Access Point is an 802.11 a/b/g dual-band, zero-touch configuration and management access point that provides secure, cost effective wireless access with advanced WLAN services for enterprise deployments. This lightweight access point provides industry-leading RF capabilities to increase wireless LAN performance, security, reliability, and scalability.
Answer option B is incorrect. LWAPP (Lightweight Access Point Protocol) is a protocol used to control multiple Wi-Fi wireless access points at once. This can reduce the amount of time spent on configuring, monitoring, or troubleshooting a large network. The system also allows network administrators to closely analyze the network. Answer option A is incorrect. A rogue access point is a wireless access point that has either been installed on a secure company network without explicit authorization from a local network administrator, or has been created to allow a cracker to conduct a man-in-the-middle attack. Rogue access points create a security threat to large organizations because anyone with access to the premises can maliciously install an inexpensive wireless router that can allow access to a secure network to unauthorized parties. Rogue access points do not employ mutual authentication.
NEW QUESTION: 2
Which of the following commands executes a recursive download of the src share located in a Samba server named SOURCES, assuming that this server allows anonymous users?
A. wget -R smB. //sources/src
B. curl -R cifs: //sources/src
C. smbget -R smB. //sources/src
D. smbmirror //sources/src
Answer: C
NEW QUESTION: 3
Why would you use the Mediator component in a Service Component Architecture (SCA) application Instead of using Oracle Service Bus?
A. The Mediator supports transactions, but Oracle Service Bus does not.
B. The Mediator is much faster than Oracle Service Bus.
C. Oracle Service Bus runs out side of a SCA application. Therefore, the Mediator is the only choice for translation and transformation tasks in an SCA application.
D. It is always better to use Oracle service Bus Instead of the Mediator.
Answer: C
Explanation:
Whereas Oracle Service Bus provides service virtualization and protocol transformations for an Oracle SOA Suite application containing multiple composites, Oracle Mediator is an intra-composite mediation component that is deployed within an application.
Note:
* Analogous to a load balancer routing HTTP traffic, the Oracle Mediator routes data from service providers to external partners. In addition, it can subscribe to and publish business events.
Using Oracle Mediator, you create routing services and rules for them. A routing service is the key
component for moving a message across the enterprise service bus - from its entry point to its exit
point. The rules determine how a message instance processed by the routing service gets to its
next destination. Using the rules, Oracle Mediator can perform the following actions:
Route: Determines the service component (BPEL process, business rule, human task, and
mediator) to which to send the messages.
Validate: Provides support for validating the incoming message payload by using a schematron or
an XSD file.
Filter: If specified in the rules, applies a filter expression that specifies the contents (payload) of a
message be analyzed before any service is invoked.
Transformation: If specified in the rules, transforms document data from one XML schema to
another, thus enabling data interchange among applications using different schemas.
NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int f(int a, int b);
int main()
{
float b;
b = f(20,10);
cout << b;
return 0;
}
int f(int a, int b)
{
return a/b;
}
A. It prints: 2
B. It prints: 10
C. It prints: 0
D. It prints: 5
Answer: A