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NEW QUESTION: 1
The BPM Program Manager, Process Owner, and Lead Developer are collaborating to define the theme and assign user stories for the next iteration. The team is planning the 7th of 15 iterations in the Release Plan for Release One. The Program Manager displays a Team Velocity chart showing that the Development team has shown significant growth in story points accepted from iterations 1 to 4 and has been leveling off to roughly 200 story points in iterations 5 and 6.
Given there are 9 iterations remaining in the release plan, the Process Owner immediately recognizes there is room for roughly 1800 story points in the remaining time for Release One. However, the backlog contains 2400 story points marked as "high" priority and another 1200 story points marked as "medium" priority. The Process Owner asks to reduce the points assessed to the high priority user stories to bring the total points down to roughly 1800 so as to make them fit in the remaining time. The Program Manager agrees.
What is wrong with this scenario?
A. Both "high" and "medium" priority stories should be included in the Release Plan meaning all user story points should be reduced by 50% to get all high/medium priority stories to fit in 1800 points remaining (2400+1200 = 3600 : 3600/2 = 1800).
B. Process Owner forgot to include a risk factor of 1.4 that should be applied to 1800 resulting in roughly 2500 story points (1.4 x 1800 = 2520) remaining in the Release. No action should be taken.
C. Team Velocity is fixed and changing the method of estimating story points mid-way through a release will not increase the scope of work that can be completed.
D. This is a conversation for a Release Planning meeting and not during Iteration Planning.
Answer: C

NEW QUESTION: 2
In the VFPv4-D32 architecture, which of the following best describes the arrangement of the registers?
A. D0 overlaps with S0, D1 with S1 etc. up to D31 and S31
B. D0..D31 overlap with S0..S63
C. D0..D15 overlap with S0..S31, and D16..D31 do not overlap with any single-precision registers
D. D0..D31 and S0..S31 are separate register banks
Answer: C

NEW QUESTION: 3
Contoso.com에서 선임 관리자로 근무합니다. Contoso.com 네트워크는 Contoso.com이라는 단일 도메인으로 구성됩니다. Contoso.com 네트워크의 모든 서버에는 Windows Server 2012 R2가 설치되어 있습니다.
하급 관리자를위한 교육을 실시하고 있습니다. 현재 NUMA (Non-Uniform Memory Architecture) 사용에 대해 논의 중입니다.
NUMA (Non-Uniform Memory Architecture)와 관련하여 다음 중 참인 것은 무엇입니까? (2 개를 선택하십시오.)
A. 프로세서가 원격 메모리에 액세스 할 수있는 것보다 빠르게 로컬 메모리에 액세스 할 수 있습니다.
B. 다중 프로세서 시스템에 사용되는 컴퓨터 아키텍처입니다.
C. 단일 프로세서 시스템에 사용되는 컴퓨터 아키텍처입니다.
D. 프로세서가 로컬 메모리에 액세스 할 수있는 것보다 빠르게 원격 메모리에 액세스 할 수 있습니다.
Answer: A,B
Explanation:
설명
NUMA는 물리적 서버의 CPU와 메모리를 NUMA 노드로 나누는 하드웨어 설계 기능입니다.
프로세스가 동일한 NUMA 노드 내에서 메모리와 CPU를 사용할 때 최상의 성능을 얻을 수 있습니다.
de가 가득 차면 메모리를 얻습니다.
프로세스에 더 많은 메모리가 필요하지만 현재 NUMA에 다른 NUMA 노드가 없는 경우 해당 프로세스에 대한 성능 비용이 발생하고 해당 물리적 서버의 다른 모든 프로세스가 가능합니다. 그렇기 때문에 가상화 엔지니어는 이를 알고 있어야 합니다. Hyper-V에는 동적 메모리가 있습니다.
비 균일 메모리 액세스 또는 NUMA (Non-Uniform Memory Architecture)는 멀티 프로세서에서 사용되는 컴퓨터 메모리 설계로, 메모리 액세스 시간은 프로세서와 관련된 메모리 위치에 따라 다릅니다. ccNUMA에서 프로세서는 로컬 메모리가 아닌 메모리, 즉 다른 프로세서에 로컬인 메모리 또는 프로세서간에 공유되는 메모리보다 빠르게 자체 로컬 메모리에 액세스 할 수 있습니다. NUMA 아키텍처는 논리적으로 SMP (Symmetric Multiprocessing) 아키텍처의 확장에서 논리적으로 따릅니다.

NEW QUESTION: 4
You have a Microsoft Dynamics 365 environment. You implement Field Service. You need to ensure that users can interact with Field Service on a mobile device. What should you do?
A. Implement the Resco Mobile CRM Woodford app.
B. Import the Field Service solution.
C. Configure the Microsoft Dynamics 365 mobile app.
D. Download the Windows Mobile Software Development Kit (SDK).
Answer: A