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NEW QUESTION: 1

A. / var / pkg / man
B. / usr / share / man
C. / opt / man
D. / usr / doc /
E. / var / man
Answer: B

NEW QUESTION: 2
You are logged into a router and have navigated to the (edit routing-options] level of the hierarchy. You have been asked to create a static route that will use 10.10.10.1 as its primary next-hop and
10.10.10.5 as its secondary next-hop.
Which command correctly configures this scenario?
A. set static route 8/8 10.10.10.1 qualified-next-hop 10.10.10.5 pref 10
B. set static route 8/8 next-hop 10.10.10.1 qualified-next-hop 10.10.10.5 preference 10
C. set static route 8/8 next-hop [10.10.10.1 10.10.10.5] pref 10
D. set static route 8/8 next-hop 10.10.10.1 secondary-next-hop 10.10.10.5 preference 10
Answer: B

NEW QUESTION: 3
A security professional is analyzing the results of a network utilization report. The report includes the following information:

Which of the following servers needs further investigation?
A. mrktg.file.srvr.02
B. hr.dbprod.01
C. R&D.file.srvr.01
D. web.srvr.03
Answer: B

NEW QUESTION: 4
You are working for a company that designs mobile applications. They maintain a server where player records are assigned to their different games. The tracking system is new and in development.
The application uses Entity Framework to connect to an Azure Database. The database holds a Player table and Game table.
When adding a player, the code should insert a new player record, and add a relationship between an existing game record and the new player record.
The application will call CreatePlayerWithGame with the correct gameIdand the playerId to start the process.
(Line numbers are included for reference only.)

For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}