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NEW QUESTION: 1
Was sind die Anforderungen für die Bearbeitung von Kundensendungen?
Es gibt 2 richtige Antworten auf diese Frage.
A. Für das Sendungsproblem ist ein Lieferschein erforderlich
B. Für die Rücksendung der Sendung ist eine Lageraufgabe zur Kommissionierung erforderlich
C. Für die Abholung der Sendung ist eine gute Quittung erforderlich
D. Für das Auffüllen der Sendung ist ein Rechnungsbeleg erforderlich
Answer: A,C
NEW QUESTION: 2
A. Option C
B. Option B
C. Option A
D. Option D
Answer: D
NEW QUESTION: 3
注:この質問は、同じまたは類似の回答の選択肢を使用する一連の質問の一部です。 回答の選択肢は、シリーズの複数の質問に対して正しいかもしれません。 各質問は、このシリーズの他の質問とは独立しています。 質問に記載されている情報や詳細がその質問に適用されます。
あなたには、銀行システム用のデータベースがあります。 データベースには、預金口座とローン口座をそれぞれ格納する2つのテーブルtblDepositAcctとtblLoanAcctがあります。 どちらの表にも次の列があります。
預金口座とローン口座の合計数を決定する必要があります。
どのTransact-SQL文を実行する必要がありますか?
A. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
C. SELECT COUNT(*)FROM (SELECT CustNoFROMtblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo=L.CustNoWHERE D.CustNo IS NULL
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
Answer: C
Explanation:
Explanation
Would list the customers with duplicates, which would equal the number of accounts.