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NEW QUESTION: 1
A perpetual inventory system uses a minimum quantity on hand to initiate purchase ordering procedures for restocking. In reviewing the appropriateness of the minimum quantity level established by the stores department, the internal auditor is least likely to consider:
A. Optimal order sizes determined by the economic order quantities model.
B. Available storage space and potential obsolescence.
C. Seasonal variations in forecasting inventory demand.
D. Stock out costs, including lost customers.
Answer: A
Explanation:
The basic economic order quantity (EOQ) model is based on the following variables: demand, variable cost per purchase order, and variable unit carrying cost. Thus, minimum stocking levels do not affect the EOQ.
NEW QUESTION: 2
DRAG DROP
Drag and drop the OSPF network type on the left to the correct traffic type category on the right.
Answer:
Explanation:
Explanation:
NEW QUESTION: 3
Refer to the exhibit.
Which statement about this output is true?
A. The remote device encrypts IKEv2 packets using key "282FE0B3B5C99A2B"
B. Identity between endpoints is verified using a certificate authority
C. The tunnel is not functional because NAT-T is not configured
D. This router has sent the first packet to establish the FlexVPN tunnel
Answer: B
NEW QUESTION: 4
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID Where o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
C. ShippingCountry, RANK() OVER (PARTITION BY c. CustomerID ORDER BY o. OrderAmount DESC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
D. ShippingCountry) cs WHERE Rnk = 1
E. ShippingCountry) cs WHERE Rnk = 1
F. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY c.CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
G. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName,
Answer: B
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